Nested match rules using awk

I have file content as

0::chkconfig --list autofs::
 autofs                 0:off   1:off   2:on    3:on    4:on    5:on    6:off

1::grep "^PROMPT=" /etc/sysconfig/init::
 PROMPT=yes

2::rpm -q prelink::
 prelink-0.4.0-2.el5

3::sysctl fs.suid_dumpable::
 fs.suid_dumpable = 0

4::stat /etc/motd::
   File: `/etc/motd'
  Size: 17              Blocks: 16         IO Block: 4096   regular file
Device: fd00h/64768d    Inode: 10125343    Links: 1
Access: (0644/-rw-r--r--)  Uid: (    0/    root)   Gid: (    0/    root)
Access: 2019-04-08 07:54:03.000000000 +0500
Modify: 2019-03-30 19:22:13.000000000 +0500
Change: 2019-03-30 19:22:13.000000000 +0500

5::stat /etc/issue::
   File: `/etc/issue'
  Size: 52              Blocks: 16         IO Block: 4096   regular file
Device: fd00h/64768d    Inode: 10125494    Links: 1
Access: (0644/-rw-r--r--)  Uid: (    0/    root)   Gid: (    0/    root)
Access: 2019-03-30 19:12:13.000000000 +0500
Modify: 2012-02-25 22:01:14.000000000 +0500
Change: 2019-03-30 23:54:57.000000000 +0500

I want first match to grab everything me between :: <everything>\d::

note: :: is followed up with \n new line (want to skip first ::)

\d for regex can be 3 places 999 (max).

The second match is to search within the first match for e.g for 5::

Access: (0644/-rw-r--r--)

grab access 0644

The second match rule criteria is not fixed and will change depending upon requirement, but the first match rule is same.

The output of final match be just the matched string and not the whole record or result.

So, far i have tried with cat org_op.2019.04.08-12.49.38 | awk 'f{print;f=0} /^3::/{f=1}'

which will give me

` fs.suid_dumpable = 0`

but its not scale to multi-lines